- · Allows a natural join based on an arbitrary condition or two columns with different names.-ON Clause
- · Performs an equijoin based on one specified column name-USING clause
Use the Oracle database for problems 1-6.
1. Join the Oracle database locations and departments
table using the location_id column. Limit the results to location 1400 only.
SELECT department_id,department_name, location_id, city
FROM departments JOIN locations USING (location_id)
WHERE location_id = 1400;
2. Join DJs on Demand d_play_list_items,
d_track_listings, and d_cds tables with the JOIN USING syntax. Include the song
ID, CD number, title, and comments in the output.
SELECT song_id, cd_number, title, comments
FROM d_cds JOIN d_track_listings USING (cd_number) JOIN d_play_list_items USING (song_id);
3. Display the city, department name, location
ID, and department ID for departments 10, 20, and 30 for the city of Seattle.
SELECT city, department_name, location_id, department_id
FROM departments JOIN locations USING (location_id)
WHERE department_id in (10, 20 , 30) AND city = 'Seattle';
OR
SELECT loc.city, dp.department_name, dp.location_id, dp.department_id
FROM departments dp INNER JOIN locations loc ON dp.location_id = loc.location_id
WHERE dp.department_id in (10, 20 , 30) AND loc.city = 'Seattle';
4. Display country name, region ID, and region
name for Americas.
SELECT country_name, region_id, region_name
FROM countries JOIN regions
USING(region_id)
WHERE region_name = 'Americas';
OR
SELECT ct.country_name, rg.region_id, rg.region_name
FROM countries ct INNER JOIN regions rg ON ct.region_id = rg.region_id
WHERE rg.region_name = 'Americas';
5. Write a statement joining the employees and
jobs tables. Display the first and last names, hire date, job id, job title,
and maximum salary. Limit the query to those employees who are in jobs that can
earn more than $12,000.
SELECT first_name, last_name,
hire_date, job_id, job_title, max_salary
FROM employees JOIN jobs USING
(job_id)
WHERE max_salary > 12000;
OR
SELECT emp.first_name,
emp.last_name, emp.hire_date, emp.job_id, jb.job_title, jb.max_salary
FROM employees emp INNER JOIN jobs jb
ON emp.job_id = jb.job_id
WHERE jb.max_salary > 12000;
6. Display job title, employee first name, last
name, and email for all employees who are stock clerks.
SELECT job_title, first_name,
last_name, LOWER(email) || 'somecomname.sometld' as email
FROM employees JOIN jobs USING(job_id)
WHERE job_title = 'Stock Clerk'
;
OR
SELECT jb.job_title, emp.first_name, emp.last_name, LOWER(emp.email) ||
'somecomname.sometld' as email
FROM employees emp INNER JOIN jobs jb
ON emp.job_id = jb.job_id
WHERE jb.job_title = 'Stock Clerk' ;
The following questions use the JOIN…ON syntax:
7. Write a statement that displays the employee
ID, first name, last name, manager ID, manager first name, and manager last
name for every employee in the employees table. Hint: this is a self-join.
SELECT emp.employee_id
AS "employee ID", emp.first_name AS "first name",
emp.last_name "last name", emp.manager_id "manager ID",
mgr.first_name "manager first name", mgr.last_name "manager last
name"
FROM employees emp LEFT JOIN employees mgr ON emp.manager_id = mgr.employee_id;
8. Use JOIN ON syntax to query and display the
location ID, city, and department name for all Canadian locations.
SELECT dp.location_id,
loc.city, dp.department_name
FROM departments dp
INNER JOIN locations loc ON
dp.location_id = loc.location_id INNER
JOIN countries ct ON loc.country_id =
ct.country_id
WHERE ct.country_name =
'Canada';
9. Query and display manager ID, department ID,
department name, first name, and last name for all employees in departments 80,
90, 110, and 190.
SELECT emp.manager_id
"Employee's Manager ID", emp.department_id "Department ID",
dpt.department_name "Department
Name", emp.first_name "First Name", emp.last_name "Last
Name"
FROM employees emp INNER JOIN departments dpt ON
emp.department_id = dpt.department_id
WHERE emp.department_id
in (80, 90, 110, 190);
10. Display employee
ID, last name, department ID, department name, and hire date for those
employees whose hire date was June 7, 1994.
SELECT emp.Employee_id
"Employee ID", emp.last_name "Last Name" ,
emp.department_id "Department ID", dpt.department_name "Department Name", emp.hire_date
"Hire Date"
FROM employees emp LEFT JOIN departments dpt ON
emp.department_id = dpt.department_id
WHERE emp.hire_date =
TO_DATE('June 7, 1994', 'fmMonth DD, YYYY');
